Odpowiedź :
[tex]-\frac{2}{3}a+\frac{5}{6} a-\frac{1}{6} =\\=-\frac{2a}{3} +\frac{5a}{6} -\frac{1}{6} =\\=-\frac{2*2a}{2*3}+\frac{5a}{6} -\frac{1}{6}=\\=-\frac{4a}{6} +\frac{5a}{6} -\frac{1}{6}=\\=-\frac{4a+5a}{6} -\frac{1}{6} =\\=\frac{a}{6} -\frac{1}{6} =\\=\frac{1}{6} a-\frac{1}{6}[/tex]