zadanie 1
(x = 3)
3² = 3×3 = 9
-3²+1 = 9+1 = 10
12-9 = 3
(x = -4)
-4²= -4×-4 = 16
-4²+1 = 16+1 = 17
12-16 = (-4)
(x= [tex]1\frac{1}{2}[/tex] )
² = [tex]1\frac{1}{2}[/tex] × [tex]1\frac{1}{2}[/tex] = [tex]2\frac{1}{4}[/tex] (2,25)
[tex]1\frac{1}{2}[/tex] ² + 1 = [tex]2\frac{1}{4}[/tex] + 1= [tex]3\frac{1}{4}[/tex]
12 - [tex]1\frac{1}{2}[/tex] = [tex]10\frac{1}{2}[/tex]
zadanie 2
a) d²+d+2 = 2²+2+2= 4+2+2 = 8
b) -y³ + 2y² + 0,5y - 0,75 = -1 + 2 × (-1) + 0,5 ×(-1)-0,75 = -1 - 2 - 0,5 - 0,75 = -4,25
zadanie 3
x - Kazik
x + 2 - Jurek
x+2-3= x-1 - Olek
[tex]\frac{x+x+2+x-1}{3}[/tex] = [tex]\frac{3x+1}{3}[/tex] = [tex]\frac{1}{3\\}[/tex] (3x+1) = x + [tex]\frac{1}{3}x[/tex] = [tex]1\frac{1}{3}x[/tex]
