pls pomocy matma daje nJ
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Odpowiedź:
a) 2 · ([tex]-2^{2}[/tex]) - [tex]\frac{1}{2} ^{3}[/tex]= -8 - [tex]\frac{1}{8}[/tex] = -8[tex]\frac{1}{8}[/tex]
b) [tex]\frac{6+5}{2-3}[/tex]=[tex]\frac{11}{-1}[/tex]=-11