Odpowiedź:
zad1
a)[tex]\sqrt{32} *\sqrt{2}=\sqrt{32*2} =\sqrt{64} =8[/tex]
b)[tex]\sqrt{4,9} *\sqrt{10} =\sqrt{4,9*10} =\sqrt{49} =7[/tex]
c)[tex]\sqrt{64} *\sqrt{25} =8*5=40[/tex]
d)[tex]\sqrt{50} :\sqrt{2} =\sqrt{50:2} =\sqrt{25}=5[/tex]
e)[tex]\frac{\sqrt{98} }{\sqrt{2} } =\sqrt{\frac{98}{2} } =\sqrt{49} =7[/tex]
zad2
[tex]a)3\sqrt{5} =\sqrt{3^2*5} =\sqrt{45}[/tex]
b)[tex]7\sqrt{3}=\sqrt{7^2*3} =\sqrt{147}[/tex]
zad4
a)[tex]\sqrt{48} =\sqrt{16*3} =4\sqrt{3}[/tex]
b)[tex]\sqrt{200} =\sqrt{100*2} =10\sqrt{2}[/tex]
zad5
a)7√2+√32=7√2+4√2=11√2
b)√20+√45=2√5+3√5=7√5
Szczegółowe wyjaśnienie:
