Odpowiedź:
[tex]a. \frac{x}{3} + 1 = \frac{5}{6} + \frac{x}{2}\frac{x}{3} - \frac{x}{2} = \frac{5}{6} - 1\\\frac{2x}{6} - \frac{3x}{6} = -\frac{1}{6}\\-\frac{x}{6} = -\frac{1}{6}\\\\ -x = -1x = 1[/tex]
[tex]b. \frac{2x-3}{4} = \frac{1}{2} +x\\2x-3=2+4x\\2x-4x=2+3\\-2x=5\\2x=-5\\x=-\frac{5}{2}[/tex]
[tex]c. \frac{x+2}{9} + \frac{x-1}{3} =1\\x+2+3x-3=9\\x+3x=9-2+3\\4x=10\\x=\frac{10}{4} = \frac{5}{2}[/tex]
[tex]d. \frac{2x+3}{5} = \frac{2-x}{3} +x\\6x+9=10-5x+15x\\6x+9=10+10x\\6x-10x=10-9\\-4x=1\\4x=-1\\x=-\frac{1}{4}[/tex]
Szczegółowe wyjaśnienie:
