Odpowiedź:
[tex](x-5)(x-2)=x-x(2-x)\\\\x^2-2x-5x+10=x-2x+x^2\\\\x^2-7x+10=-x+x^2\\\\x^2-7x+x-x^2=-10\\\\-6x=-10\ \ /:(-6)\\\\x=\frac{10}{6}\\\\x=\frac{5}{3}\\\\x=1\frac{2}{3}[/tex]
