Odpowiedź:
[tex]1. \: a)\frac{3}{8} + \frac{5}{6} = \frac{12}{24} + \frac{20}{24} = \frac{32}{24} = 1 \frac{8}{24} = 1 \frac{1}{3} \\ b) \frac{3}{8} \times \frac{5}{6} = \frac{5}{16} \\ c) \frac{3}{8} \div \frac{5}{6} = \frac{3}{8} \times \frac{6}{5} = \frac{18}{40} = \frac{9}{20} \\ d) \frac{5}{6} \div \frac{3}{8} = \frac{5}{6} \times \frac{8}{3} = \frac{40}{18} = 2 \frac{4}{18} = 2 \frac{2}{9} [/tex]
[tex]2. \: a)2 \frac{3}{4} - 1 \frac{1}{2} \times \frac{2}{3} = 2 \frac{3}{4} - \frac{3}{2} \times \frac{2}{3} = 2 \frac{3}{4} - 1 = 1 \frac{3}{4} \\ b)3 \frac{1}{5} \times (5 \frac{1}{4} - 2 \frac{3}{4} ) = 3 \frac{1}{5} \times 2 \frac{2}{4} = \frac{16}{5} \times \frac{10}{4 } = 8[/tex]
[tex]3. mendel = 15 \\ kopa = 15 \times 4 = 60 \\ tuzin = \frac{3}{5} mendla = \frac{3}{5} \times 15 = 9 \\ \frac{9}{60} = \frac{3}{20} [/tex]
