Zadanie w załączniku na jusz. Daje naj. ​

Zadanie W Załączniku Na Jusz Daje Naj class=

Odpowiedź :

[tex]2\dfrac{1}{3}-(-2\dfrac{1}{3}):(-4\dfrac{2}{3})\cdot\dfrac{7}{3}+(-\dfrac{5}{6})-\dfrac{2}{3}=2\dfrac{1}{3}-\dfrac{7}{3}:\dfrac{14}{3}\cdot\dfrac{7}{3} -\dfrac{5}{6}-\dfrac{2}{3}=\\\\= \dfrac{7}{3}-\dfrac{7}{\not\!3}\cdot\dfrac{\not\!3}{\not\!\!14_{2}}\cdot\dfrac{\not\!7}{3} -\dfrac{5}{6}-\dfrac{4}{6}=\dfrac{14}{6}-\dfrac{7}{6}-\dfrac{9}{6}=\dfrac{7}{6}-\dfrac{9}{6}=-\dfrac{2}{6}=\boxed{-\dfrac{1}{3}}[/tex]