Odpowiedź:
[tex]a)\frac{25}{2}:\frac{1}{5}*\frac{25}{10}=\frac{25}{2}*5*\frac{25}{10}=\frac{625}{4}=156\frac{1}{4}[/tex]
[tex]3\frac{3}{4}+\frac{28}{100}*\frac{25}{14}=3\frac{3}{4}+\frac{1}{2}=3\frac{3}{4}+\frac{2}{4}=3\frac{5}{4}=4\frac{1}{4}[/tex]
[tex]b)\frac{57}{10}:(\frac{38}{7}-\frac{38}{10})=\frac{57}{10}:(\frac{380}{70}-\frac{266}{70})=\frac{57}{10}*\frac{70}{144}=\frac{7}{2}=3\frac{1}{2}[/tex]
[tex]4,08-\frac{208}{100} *\frac{25}{13}=4,08-\frac{16}{4}=4,08-4=0,08[/tex]
[tex]c)\frac{25}{10}*\frac{9}{2}-\frac{117}{20}*\frac{10}{9}=\frac{225}{20}-\frac{13}{2}=\frac{45}{4}-\frac{26}{4}=\frac{19}{4}=4\frac{3}{4}[/tex]
[tex]\frac{5}{2}*\frac{13}{10}+\frac{39}{8}:\frac{125}{100}=\frac{13}{4}+\frac{39}{8}*\frac{100}{125}=\frac{13}{4}+\frac{39}{10}=\frac{65}{20}+\frac{78}{20}=\frac{143}{20}=7\frac{3}{20}[/tex]
[tex]d)3*(\frac{5}{3})^{2}-2*(\frac{5}{10})^{3}=3*\frac{25}{9}-2*\frac{125}{1000}=\frac{25}{3}-\frac{1}{4}=\frac{100}{12}-\frac{3}{12}=\frac{97}{12}=8\frac{1}{12}[/tex]
[tex](5\frac{1}{4}-5\frac{5}{100})^{2}-\frac{1}{25}=(5\frac{25}{100}-5\frac{5}{100})^{2}-\frac{1}{25}=(\frac{1}{5})^{2}-\frac{1}{25}=\frac{1}{25}-\frac{1}{25}=0[/tex]
Szczegółowe wyjaśnienie: