Odpowiedź:
a) 2/x+2/x+3= 2/x+2/x+ 3x/x= (4+3x)/x x≠0
x∈ R-{0}
b) 6/(x-2) -3= 6/(x-2)- 3(x-2)/(x-2)= (6-3(x-2)/(x-2)= (6-3x+6)/(x-2)= -3x/(x-2)
x-2≠0 x≠2
x∈ R-{2}
c) 8/x²-16+4/(x-4)= 8(x-4)/x²(x-4)-16x²(x-4)/x²(x-4)+4x²/x²(x-4)=(8x-32-16x³+64x²+4x²)/x²(x-4)=(16x³+68x²+8x-32)/x²(x-4)
x²(x-4)≠0
x²≠0 v x-4≠0
x≠0 v x≠4
x∈ R-{0,4}
Szczegółowe wyjaśnienie:
