Odpowiedź:
[tex]A.\ \ \sqrt{5-2\frac{3}{4}}*2=\sqrt{4\frac{4}{4}-2\frac{3}{4}}*2=\sqrt{2\frac{1}{4}}*2=\sqrt{\frac{9}{4}}*2=\frac{3}{\not2}*\not2=3\\\\\\B.\ \ \sqrt{5-2\frac{2}{9}}*3=\sqrt{4\frac{9}{9}-2\frac{2}{9}}*3=\sqrt{2\frac{7}{9}}*3=\sqrt{\frac{25}{9}*3}=\frac{5}{\not3}*\not3=5\\\\\\C.\ \ \sqrt[3]{5^2+2}=\sqrt[3]{25+2}=\sqrt[3]{27}=3\\\\\\D.\ \ \sqrt{5^2-2^2}=\sqrt{25-4}=\sqrt{21}\\\\\\E.\ \ \sqrt[3]{\frac{5^2}{2}*4-23}=\sqrt[3]{\frac{25}{\not2_{1}}*\not4^2-23}=\sqrt[3]{50-23}=\sqrt[3]{27}=3[/tex]
[tex]Odp.\ \ A\ \ ,\ \ C\ \ ,\ \ E[/tex]
