Odpowiedź:
a) [tex]\frac{3}{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2} } =\frac{3\sqrt{2} }{2}[/tex]
b)[tex]\frac{15}{\sqrt{5} } * \frac{\sqrt{5} }{\sqrt{5} } =\frac{15\sqrt{5} }{5}=3\sqrt{5}[/tex]
c)[tex]\frac{2\sqrt{3} }{3\sqrt{6} } * \frac{\sqrt{6} }{\sqrt{6} } =\frac{2\sqrt{18} }{3*6}= \frac{2\sqrt{18} }{18} =\frac{\sqrt{18} }{9} = \frac{3\sqrt{2} }{9} =\frac{\sqrt{2} }{3}[/tex]
d)[tex]\frac{\sqrt{7} }{\sqrt{70} } *\frac{\sqrt{70} }{\sqrt{70} } =\frac{\sqrt{490} }{70} =\frac{7\sqrt{10} }{70} =\frac{\sqrt{10} }{10}[/tex]
e)[tex]\frac{20}{\sqrt{10} } * \frac{\sqrt{10} }{\sqrt{10} } =\frac{20\sqrt{10} }{10}=2\sqrt{10}[/tex]
f)[tex]\frac{4\sqrt{6} }{9\sqrt{12} } * \frac{\sqrt{12} }{\sqrt{12} } =\frac{4\sqrt{72} }{9*12}=\frac{4\sqrt{72} }{108} =\frac{\sqrt{72} }{27} = \frac{6\sqrt{2} }{27} =\frac{2\sqrt{2} }{9}[/tex]
