Odpowiedź:
[tex]-5(\frac{1}{25}x+\frac{1}{15}xy-\frac{1}{10}y)-2(\frac{1}{10}-x-\frac{1}{4}y)=-\frac{1}{5}x-\frac{1}{3}xy+\frac{1}{2}y-\frac{1}{5}+2x+\frac{1}{2}y=\\\\=-\frac{1}{5}x-\frac{1}{3}xy+\frac{2}{2}y-\frac{1}{5}+1\frac{5}{5}x=1\frac{4}{5}x-\frac{1}{3}xy+y-\frac{1}{5}[/tex]
