Hej!
Oto Twoja odpowiedź:
a)
[tex]pole \: rombu = \frac{e \times f}{2} [/tex]
e = 6,4 cm
f = 14 cm
[tex]p = \frac{6.4cm \times 14cm}{2} = \frac{89.6cm}{2} = 44.8 {cm}^{2} [/tex]
b)
pole równoległoboku = a * h
a = 8 cm
h = 4,8 cm
P = 8 cm * 4,8 cm = 38,4 cm2
c)
[tex]pole \: trapezu = \frac{(a + b) \times h}{2} [/tex]
a = 7 cm
b = 13 cm
h = 2,8 cm
[tex]p = \frac{(7cm + 13cm) \times 2.8cm}{2} = \frac{20cm \times 2.8cm}{2} = \frac{56cm}{2} = 28 {cm}^{2} [/tex]
Pozdrawiam™
