Odpowiedź:
[tex](9x)^2=9^2*x^2=81x^2\\\\\\(2n)^5=2^5*n^5=32n^5\\\\\\(\frac{5}{y})^3=\frac{5^3}{y^3}=\frac{125}{y^3}\\\\\\(\frac{a}{3})^3=\frac{a^3}{3^3}=\frac{a^3}{27}[/tex]
