[tex]2x^{2} \geq 7x-5\\\\2x^{2}-7x+5 \geq 0\\\\a = 2, \ b = -7, \ c = 5\\\\\Delta = b^{2}-4ac = (-7)^{2}-4\cdot2\cdot5 = 48-40 = 9\\\\\sqrt{\Delta} = \sqrt{9} = 3\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{-(-7)-3}{2\cdot2} = \frac{7-3}{4} =\frac{4}{4} = 1\\\\x_2 =\frac{-(-7)+\sqrt{\Delta}}{2a} =\frac{7+3}{4} = \frac{10}{4} = 2,5\\\\a > 0, ramiona \ paraboli \ skierowane \ do \ gory\\\\x \in (-\infty;1> \ \cup \ <2,5; +\infty)[/tex]
