Odpowiedź:
[tex]\begin{cases}2(x-2y)+3(x+2y)=23\\3(x-y)+2(3x+y)=0\end{cases}\\\\\\\begin{cases}2x-4y+3x+6y=23\\3x-3y+6x+2y=0\end{cases}\\\\\\\begin{cases}5x+2y=23\\9x-y=0\ \ /*2\end{cases}\\\\\\\begin{cases}5x+2y=23\\18x-2y=0\end{cases}\\--------\\23x=23\ \ /:23\\x=1\\\\9*1-y=0\\\\9-y=0\\\\-y=-9\ \ /*(-1)\\\\y=9\\\\\\\begin{cases}x=1\\y=9\end{cases}[/tex]
