Odpowiedź :
Odpowiedź:
zad 1
[tex]a) \frac{2}{3} \times 0 = 0 \\ b) \frac{2}{3} + 0 = \frac{2}{3} \\ c) \frac{2}{3} \times 1 = \frac{2}{3} \\ d) \frac{2}{3} + 1 = 1 \frac{2}{3} \\ e) \frac{2}{3} - 0 = \frac{2}{3} \\ f)0 \div \frac{2}{3} = 0 \times \frac{3}{2} = 0[/tex]
zad. 2
[tex]a) \frac{1}{2} + \frac{1}{2} \times 5 = \frac{1}{2} + \frac{5}{2} = \frac{6}{2} = 3 \\ b)( \frac{1}{2} + \frac{1}{2} ) \times 5 = 1 \times 5 = 5 \\ c) \frac{4}{5} + \frac{3}{5} \times \frac{2}{3} = \frac{4}{5} + \frac{2}{5} = \frac{6}{5} = 1 \frac{1}{5} [/tex]
[tex]d)3 - \frac{2}{7} + \frac{5}{7} = 3 3/7 [/tex]
zad 1
[tex] \frac{2}{3} \times 0 = 0[/tex]
[tex] \frac{2}{3} + 0 = \frac{2}{3}[/tex]
[tex]\frac{2}{3} \times 1 = \frac{2}{3}[/tex]
[tex]\frac{2}{3} + 1 =1 \frac{2}{3}[/tex]
[tex]\frac{2}{3} - 0 = \frac{2}{3}[/tex]
[tex]0 \div \frac{2}{3} = 0[/tex]
zad 2
[tex] \frac{1}{2} + \frac{1}{2} \times 5 = \frac{1}{2} + \frac{5}{2} = \frac{6}{2} = 3[/tex]
[tex](\frac{1}{2} + \frac{1}{2}) \times 5 = 1 \times 5 = 5[/tex]
[tex] \frac{4}{5} + \frac{3}{5} \times \frac{2}{3} = \frac{4}{5} + \frac{6}{15 } = \frac{12}{15} + \frac{6}{15} = \frac{18}{15} = 1 \frac{3}{15} = 1 \frac{1}{5} [/tex]
[tex]3 - \frac{2}{7} + \frac{5}{7} = 2 \frac{7}{7} - \frac{2}{7} + \frac{5}{7} = 2 \frac{5}{7} + \frac{5}{7} = 2 \frac{10}{7} = 3 \frac{3}{7} [/tex]