[tex]dane:\\F = 200 \ N\\S = 0,02 \ m\times 0,05 \ m = 0,001 \ m^{2}\\szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\p = \frac{200 \ N}{0,001 \ m^{2}}\\\\p = 200 \ 000 \ Pa = 200 \ kPa\\\\(1 \ kPa = 1000 \ Pa)[/tex]
Odp. Szukane ciśnienie p = 200 kPa.
