Odpowiedź:
[tex]a) 5-(m+5-k)+(3k-7m+3)=5-m-5+k+3k-7m+3=-8m+4k+3[/tex]
[tex]b)2x^{2} *(x-8)-3x*(y-6x^{2} )=2x^{3} -16x^{2} -3xy+18x^{3} =20x^{3} -16x^{2} -3xy[/tex]
[tex]c)6a-\frac{12}{3} -15a+\frac{10}{5} +(-2a+8b-1):2=6a-4-15a+2+\frac{-2a+8b-1}{2} =-9a-2+\frac{-2a+8b-1}{2} =\frac{-20a-5+8b}{2}[/tex]
