Odpowiedź:
zad. 1
a=4 cm
h=5
[tex]P_{p} = \frac{ {a}^{2} \sqrt{3} }{4} = \frac{ {4}^{2} \times \sqrt{3} }{4} = \frac{16 \sqrt{3} }{4} = 4 \sqrt{3} [/tex]
[tex]P_{b} = \frac{1}{2} \times 4 \times 5 = \frac{1}{2} \times 20 = 10[/tex]
[tex]P_{c} = P_{p} + 3 \times P_{b} = 4 \sqrt{3} + 3 \times 10 = 4 \sqrt{3} + 30[/tex]
zad. 2
[tex]P_{p} = 64 {cm}^{2} \\ 64 {cm}^{2} = {a}^{2} \\ a = 8cm[/tex]
h=6 cm[tex]P_{b} = \frac{1}{2} \times 8 \times 6 = \frac{1}{2} \times 48 = 24[/tex]
[tex]P_{c} = P_{p} + 4 \times P_{b} = 64 + 4 \times 24 = 64 + 96 = 160 {cm}^{2} [/tex]
