Odpowiedź:
[tex]e)\ \ \frac{2x-1}{x+2}=\frac{2*3-1}{3+2}=\frac{6-1}{5}=\frac{5}{5}=1\\\\\\f)\ \ 8xy-x-y=8*6*(-0,5)-6-(-0,5)=48*(-0,5)-6+0,5=\\\\=-24-6+0,5=-30+0,5=-29,5\\\\\\g)\ \ x^2-xy+y^2=2^2-2*(-2)+(-2)^2=4+4+4=12\\\\\\h)\ \ x^3-\frac{1}{2}x^2+1=(-2)^3-\frac{1}{2}*(-2)^2+1=-8-\frac{1}{\not2_{1}}*\not4^2+1=-8-2+1=\\\\=-10+1=-9[/tex]