[tex]1)\\\\ -(5p+1r-s)= - 5p-1r+s\\\\2)\\\\-3(s+2)=-3s-6\\\\3)\\\\\frac{8s-4t+1}{-2}=\frac{8s}{-2}-\frac{4t}{-2}-\frac{1}{2}=-4s-+2t-\frac{1}{2}\\\\4)\\\\-6x-(3x-y)+4(-2x+y)=-6x- 3x+ y -8x+4y=5y-17x[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie:
-(5p-1r-s)= -5p +r+s
-3(x+2)=-3x-6
(8x-4t+1)/-2= -4x+2t-1/2
-6x-(3x-y)+4(-2x+y)=-6x-3x+y-8x+4y= -17x+5y
