Odpowiedź:
[tex]\left \{ {{5x+y=8} \atop {4x+3y=2}} \right.\\\left \{ {{y=8-5x} \atop {4x+3(8-5x)=2}} \right. \\\left \{ {{y=8-5x} \atop 24-11x=2}} \right.\\\left \{ {{y=8-5x} \atop {-11x=-22}} \right.\\\left \{ {{x=2} \atop {y=8-5*2}} \right. \\\left \{ {{x=2} \atop {y=-2}} \right.[/tex]
Pozdrawiam
Szczegółowe wyjaśnienie:
