Szczegółowe wyjaśnienie:
a)
[tex]6 \frac{1}{4} - ( \frac{17}{5} - \frac{43}{20}) - 4 \frac{3}{10} \times ( \frac{7}{4} + \frac{43}{20} - \frac{39}{10} = 6 \frac{1}{4} - \frac{5}{4} - 4 \frac{3}{10} \times 0 = 6 \frac{1}{4} - \frac{5}{4} - 0 = \frac{25}{4} - \frac{5}{?4} = 5[/tex]
b)
[tex] \frac{23}{4} - \frac{3}{4} \times ( \frac{22}{5} - \frac{34}{10} ) - \frac{19}{8} + ( \frac{13}{4} - \frac{5}{3} ) = \frac{23}{4} - \frac{3}{4} \times 1 - \frac{19}{8} + \frac{19}{12} = \frac{23}{4} - \frac{3}{4} - \frac{19}{8} + \frac{19}{12} = \frac{101}{24} = 4 \frac{5}{24} [/tex]
c)
[tex] \frac{61}{5} - ((3 + 2) + ( \frac{5}{6} + \frac{1}{2} )) + ( \frac{43}{10} - \frac{5}{3} ) = \frac{61}{5} - (5 + \frac{4}{3} ) + \frac{79}{30} = \frac{61}{5} - (6 + \frac{1}{3}) + \frac{79}{30} = \frac{61}{5} - \frac{19}{3} + \frac{79}{30} = \frac{17}{2} [/tex]
d)
[tex] \frac{17}{6} + 6 - ( \frac{10}{3} - \frac{7}{4} ) + (7 - \frac{43}{12}) = \frac{17}{6} + 6 - \frac{19}{12} + \frac{41}{12} = \frac{32}{3} = 10 \frac{2}{3} [/tex]
