Odpowiedź :
(2x-2)(-x+1)(5x-10)=0
2(x-1)·(-1)·(x-1)·5(x-2)=0
-10(x-1)²(x-2)=0|:(-10)
(x-1)²(x-2)=0
x-1=0 ∨ x-2=0
x=1 ∨ x=2
x ∈ {1,2}
(2x-2)(-x+1)(5x-10)=0
2(x-1)·(-1)·(x-1)·5(x-2)=0
-10(x-1)²(x-2)=0|:(-10)
(x-1)²(x-2)=0
x-1=0 ∨ x-2=0
x=1 ∨ x=2
x ∈ {1,2}