[tex]dane:\\m = 25 \ kg\\r = 15 \ m\\F_{d} = 30 \ N = 30 \ kg\cdot\frac{m}{s^{2}} \\szukane:\\v = ?\\\\Rozwiazanie\\\\F_{d} = \frac{mv^{2}}{r} \ \ /\cdot r\\\\mv^{2} = F_{d}\cdot r \ \ /:m\\\\v^{2} = \frac{F_{d}\cdot r}{m}\\\\v = \sqrt{\frac{F_{d}\cdot r}{m}}}\\\\v=\sqrt{\frac{30 \ kg\cdot m/s^{2}\cdot15 \ m}{25 \ kg}}} = \sqrt{18\frac{m^{2}}{s^{2}}} = \sqrt{9\cdot2} \ \frac{m}{s} =3\sqrt{2}\frac{m}{s}\\\\v\approx4,24\frac{m}{s}[/tex]
