Odpowiedź:
[tex]a)\ \ 7\frac{1}{3}-3,5=7\frac{1}{3}-3\frac{1}{2}=7\frac{2}{6}-3\frac{3}{6}=6\frac{8}{6}-3 \frac{3}{6}=3\frac{5}{6}\\\\\\b)\ \ 4\frac{3}{4}+1,8=4,75+1,8=6,55\\\\\\c)\ \ 8,5:2\frac{5}{6}=\frac{85}{10}:\frac{17}{6}=\frac{\not17^1}{\not2_{1}}*\frac{\not6^3}{\not17_{1}}=3\\\\\\d)\ \ 5,25*1\frac{5}{7}=\frac{525}{100}*\frac{12}{7}=\frac{\not21^3}{\not4_{1}}*\frac{\not12^3}{\not7_{1}}=3*3=9[/tex]
