Odpowiedź :
Figura ABC
[tex]a = 4\\h = 4\\\\P_{ABC} = \frac{1}{2}ah = \frac{1}{2}\cdot4\cdot4 = 8[/tex]
Figura EFGH
[tex]d_1 = d_2 = 6\\\\P_{EFGH} = \frac{d_1\cdot d_2}{2} = \frac{6\cdot6}{2} = 18[/tex]
Figura IJKL
[tex]a = 6\\b = 5\\h = 3\\\\P_{IJKL} = \frac{a+b}{2}\cdot h = \frac{6+5}{2}\cdot3 = \frac{11}{2}\cdot3 = \frac{33}{2} = 16,5[/tex]
Figura MNOP
[tex]a = 2\\h = 5\\\\P_{MNOP} = a\cdot h = 2\cdot 5 = 10[/tex]
(jako jednostkę przyjęto 1 kratkę)