b)
[tex]f(x) = x^{3}-3x\\\\A(-1, -3) \ \ \rightarrow \ \ x = -1, \ y = -3\\\\L = f(x) = -3\\\\P = x^{3}-3x = (-1)^{3}-3(-1) = -1 +3 = 2\\\\L \neq P[/tex]
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[tex]B(\sqrt{5}, -\sqrt{5})\\\\L = -\sqrt{5}\\\\P = (\sqrt{5})^{3}-3\cdor\sqrt{5} = 5\sqrt{5}-3\sqrt{5} = 2\sqrt{5}\\\\L\neq P[/tex]
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[tex]C(\sqrt[3]{-8}, log_{2}0,25)\\\\x = \sqrt[3]{-8} = -2\\y = log_{2}0,25 = log_{2}\frac{25}{100} = log_{2}\frac{1}{4} = log_{2}2^{-2} = -2\\\\C(-2, -2)\\\\L = -2\\\\P = (-2)^{3}-3\cdot(-2) = -8 + 6 = -2\\\\L = P[/tex]
Odp. Do wykresu funkcji b) należy punt C.
