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3(2a–4d)=
2(5a–3d)=
4(2c–3d)=
5(8a–3b)=
6(2x–4y)=

–2(3a+4b)=
–4(d+3s)=
–3(v+3w)=
–6(2x+3y)=
–5(3n+4m)=


–3(2a–4d)=
–2(5a–3d)=
–4(2c–3d)=
–5(8a–3b)=
–6(2x–4y)=
–3(–2a–4d)=
–2(–5a–3d)=
–4(–2c+3d)=
–5(–8a+3b)=
–6(–2x–4y)=

–2(–3a+4b)=
–4(d–3s)=
–3(–v+3w)=
–6(–2x+3y)=
–5(–3n–4m)=
2a+3b+5a+2b=
4x+5y+4y+5x=
7s+5z+4s+6z=
4b+9c+78b+3c=
21a+7b-3a-4b=
13a-4b+12a+8b=
8h+6g-2h-5g=
2a+7b-a-8b=

4a-7b-5a+7b=
2a-9k-4a+7k=
3x-6v+5x-8v=
34v-5w+45v+5w=
3b-9a+8b-4b
–3d+5a–4d–8a=
–3x–7y–4x-8y=
3w+9y+(–7w)+(–6y)=


Odpowiedź :

Odpowiedź:

3(2a-4d) = 6a - 12 d

2(5a-3d) = 10a - 6 d

4(2c-3d) = 8c - 12 d

5(8a - 3b) = 40a - 15b

6(2x-4y) = 12x - 24 y

wyniki same bed podawac po koleji

= -6a -8b

= -4d - 12s

= -3v -9w

= -12x - 18y

= -15n - 20 m

= -6a + 12 d

= -10a + 6d

= -8c + 12d

= -40a + 15 b

= - 12 x + 24 y

= 6a + 12d

= 10a + 6d

= 8c - 12d

= 40a - 15b

= 12x + 24y

= 6a - 8b

= -4d + 12s

= 3v -9w

= 12x - 18y

= 15n +20m

= 7a + 5b

= 9x +9y

= 11s +11 z

= 82b + 12c ???

= 18a +3b

= g + 6h

= a - b

=  -a

= -2a -2k

= 8x -14v

= 79v

= -9a + 7b

= -3a -7d

= -7x -15y

= -4w + 3y

Szczegółowe wyjaśnienie: