[tex]x= -3\frac{1}{5}+1,4=-3\frac{1}{5}/_{*2} +1\frac{4}{10} =-3\frac{2}{10} +1\frac{4}{10} =-1\frac{8}{10}=-1\frac{4}{5}\\y=-1\frac{2}{9}-(-2\frac{1}{3}/_{*3})=-1\frac{2}{9}+2\frac{3}{9}=1\frac{1}{9}\\x*y=-1\frac{4}{5} *1\frac{1}{9}=-\frac{9}{5} *\frac{10}{9}=-\frac{2}{1}=-2\\x:y=-1\frac{4}{5}:1\frac{1}{9} =-\frac{9}{5}:\frac{10}{9}=-\frac{9}{5}*\frac{9}{10}=1\frac{81}{50}=-1\frac{31}{50}/_{*2} =-1\frac{62}{100}=-1,62[/tex]Odpowiedzi A i D
