c)
[tex]\dfrac{22 - 3 \cdot 4}{5+3 \cdot 9} : 1\dfrac{1}{4}= \dfrac{22 - 12}{5+27} : \dfrac{5}{4} = \dfrac{10}{32} \cdot \dfrac{4}{5} =\dfrac{\not{5}^1}{\not{16}_4} \cdot \dfrac{\not{4}^1}{\not{5}_1} =\dfrac{1}{4}[/tex]
d)
[tex]\dfrac{3,4-1,8}{0,8} \cdot \dfrac{\frac{1}{6} +\frac{3}{4}- 0,5}{2,4:0,6} =\dfrac{1,6}{0,8} \cdot \dfrac{\frac{2}{12} +\frac{9}{12}- \frac{1}{2}}{24:6} =\dfrac{16}{8} \cdot \dfrac{\frac{11}{12}- \frac{6}{12}}{4} =2\cdot \dfrac{\frac{5}{12}}{4} = \\\\ = 2 \cdot ({\frac{5}{12} : 4) = 2 \cdot ({\frac{5}{12} \cdot \frac{1}{4}) = \not{2}^1 \cdot \frac{5}{\not{48}_{24}} =\frac{5}{24}[/tex]
