Odpowiedź :
Odpowiedź:
t - czas = 14 min = 14/60 h = 7/30 h
s - droga = 10 m = 10 : 1000 = 1/100 km
v - prędkość żółwia = s : t = 1/100 km : 1 7/30 h = 1/100 km : 37/30 h =
= 1/100 km * 30/37 (1/h) = 30/3700 km/h = 3/370 km/h ≈ 0,008 km/h
[tex]s = 10 \ m = \frac{1}{100} \ km\\t = 1 \ h \ i \ 14 \ min = 1 \ h \ i \ \frac{14}{60} \ h = 1 \ h \ i \ \frac{7}{30} \ h = \frac{37}{30} \ h\\\\v = \frac{s}{t}=\frac{\frac{1}{100}km}{\frac{37}{30}h} = \frac{1}{100}\cdot\frac{30}{37}} \ \frac{km}{h} = \frac{3}{370} \ \frac{km}{h}}\approx0,008 \ \frac{km}{h}[/tex]