Odpowiedź:
1 etap
[tex]7 \frac{1}{3} km[/tex]
2 etap
[tex]7 \frac{1}{3} km + 3 \frac{5}{6} km = 7 \frac{2}{6} + 3 \frac{5}{6} = 8 + 3\frac{1}{6} = 11 \frac{1}{6} km[/tex]
3 etap
[tex]7 \frac{1}{3} - 1 \frac{3}{4} = 7 \frac{4}{12} - 1 \frac{9}{12} = 5 \frac{7}{12} [/tex]
suma
[tex]7 \frac{1}{3} + 11 \frac{1}{6} + 5 \frac{7}{12} = 7 \frac{4}{12} + 11 \frac{2}{12} + 5 \frac{7}{12} = 24 \frac{1}{12} [/tex]
