Odpowiedź:
1.
A = (- 5 , 3 ) , B = (- 7 , 3 )
xa = - 5 , xb = - 7 , ya = 3 , yb = 3
IABI = √[(xb - xa)² + (yb - ya)²] = √[(- 7 + 5)² + (3 - 3)²] = √(- 2)² = √4 = 2 [j] więc FAŁSZ
2.
C = (4 , - 2 ) , D = (4 , 5 )
xc = 4 , xd = 4 , ya = - 2 , yb = 5
ICDI = √[(xd - xc)² + (yd - yc)²] = √[(4 - 4)² + (5 + 2)²] = √7² = 7 więc PRAWDA