[tex]krawedz\ podstawy\ :\ a= 2\\ wysokosc\ ostroslupa: H=9 \\\\objetosc\ ostroslupa:\\\\V=\frac{1}{3} P_{p}*H\\\\podstawa\ to\ szesciokat\ foremny:\\\\ P_{p}=\frac{3a^2\sqrt{3}}{2}=\frac{3*2^2\sqrt{3}}{2}=\frac{\not{12}^6\sqrt{3}}{\not{2}^1}=6\sqrt{3}\ [j^2]\\\\V=\frac{1}{\not{3}^1}*\not{6}^2\sqrt{3}*9=18\sqrt{3}\ [j^3][/tex]
