Odpowiedź :
[tex]a)\sqrt{3^2+4^2} =\sqrt{9+15} =\sqrt{25} =\sqrt[2]{5^2} =5[/tex]
[tex]b)\sqrt{9\sqrt{16} } =\sqrt{9\cdot4} =\sqrt{36} =\sqrt[2]{6^2} =6[/tex]
[tex]c)\sqrt{16} +\sqrt{36} =\sqrt[2]{4^2} +\sqrt[2]{6^2} =4+6=10[/tex]
[tex]d)\sqrt{\frac{\not98}{\not128} } =\sqrt{\frac{49}{64} } =\frac{\sqrt{49} }{\sqrt{64} } =\frac{\sqrt[2]{7^2} }{\sqrt[2]{8^2} } =\frac{7}{8}[/tex]