Odpowiedź:
zad.1
a. 3(a-b)-(2a-b)+1=3a-3b-2a+b+1=a-2b+1
a=2/3 b=-3
a-2b+1=2/3-2(-3)+1=2/3+6+1=7 2/3
b. b^2-2a+5=(-3)^2-2•2/3+5=9-4/3+5=
=9-1 1/3+5=12 2/3
c. 0,75a-2(b^3-3)=(3/4)a-2b^3+6=3/4•2/3-2(-3)^3+6=
=1/2+54+6=60 1/2
zad.2
a. -(2,4y+6)-(1,8y+2)+3y=-2,4y-6-1,8y-2+3y=-1,2y-8
b. 2(x^2-y)-(y-x^2)+2x^2=2x^2-2y-y+x^2+2x^2=
=5x^2-3y
0,75 a - 2( b³-3) = 0,75 ×2/3 -2 [ (-3)³ - (-3)]= 3/4 × 2/3 - 2 (-9+3) = 1/2 + 12 =
121/2.
Zad 2
-(2,4y+6)-(1,8y+2)+3y = -2,4y -6 -1,8y- 2 +3y= -1,2 y -8
2(x²-y) - (y-x²) + 2x² = 2x²-2y-y+x²+2x²= 5x² - 3y
Szczegółowe wyjaśnienie:
