Odpowiedź :
[tex]a)\\\\6\frac{1}{4}-(3\frac{2}{5}-2\frac{3}{20})-4\frac{3}{10}*(1\frac{3}{4}+2\frac{3}{20}-3\frac{9}{10})=\\\\=6\frac{1}{4}-(3\frac{8}{20}-2\frac{3}{20})-4\frac{3}{10}*(1\frac{15}{20}+2\frac{3}{20}-3\frac{18}{20})= \\\\=6\frac{1}{4 }-1\frac{5}{20} - \frac{43}{10}*( 3\frac{18}{20}-3\frac{18}{20})= \\\\=6\frac{1}{4 }-1\frac{1}{4 } - \frac{43}{10}*0= 5-0=5[/tex]
[tex]b)\\\\5\frac{3}{4}-\frac{3}{4}*(4\frac{2}{5}-\frac{34}{10})-2\frac{3}{8}+(3\frac{1}{4}-1\frac{2}{3})=\\\\=5\frac{3}{4}-\frac{3}{4}*( \frac{22}{5}-\frac{34}{10})-2\frac{3}{8}+(3\frac{3}{12}-1\frac{8}{12})=\\\\=5\frac{3}{4}-\frac{3}{4}*( \frac{44}{10}-\frac{34}{10})-2\frac{3}{8}+(2\frac{15}{12}-1\frac{8}{12})= \\\\=5\frac{3}{4}-\frac{3}{4}* 1-2\frac{3}{8}+ 1\frac{7}{12}= \\\\=5\frac{18}{24}-\frac{18}{24} -2\frac{9}{24}+ 1\frac{14}{24}=\\\\=5-2\frac{9}{24}+1\frac{14}{24}=2\frac{15}{24}+1\frac{14}{24}=3\frac{29}{24}=4\frac{5}{24}[/tex]
[tex]c)\\\\12\frac{1}{5}-(3\frac{5}{6}+2\frac{1}{2})+(4\frac{3}{10}-1\frac{2}{3})=12\frac{1}{5}-(3\frac{5}{6}+2\frac{3}{6})+(4\frac{9}{30}-1\frac{20}{30})=\\\\=12\frac{1}{5}-5\frac{8}{6} +(3\frac{39}{30}-1\frac{20}{30})= 12\frac{6}{30}-5\frac{40}{30} +2\frac{19}{30}= 11\frac{36}{30}-6\frac{10}{30} +2\frac{19}{30}= \\\\= 5\frac{26}{30}+2\frac{19}{30}=7\frac{45}{30}=8\frac{15}{30}=8\frac{1}{2}[/tex]
[tex]d)\\\\2\frac{5}{8}+6-(3\frac{1}{3}-1\frac{3}{4})+(7-3\frac{7}{12})=8\frac{5}{8} -(3\frac{4}{12}-1\frac{9}{12})+(6\frac{12}{12}-3\frac{7}{12})=\\\\=8\frac{5}{8} -(2\frac{16}{12}-1\frac{9}{12})+ 3\frac{5}{12} =8\frac{5}{8} - 1\frac{7}{12} + 3\frac{5}{12} = 8\frac{15}{24} - 1\frac{14}{24} + 3\frac{10}{24} = \\\\=7\frac{1}{24}+3\frac{10}{24}= 10\frac{11}{24}[/tex]