[tex]a = 2^7, \ b = (\frac{1}{2})^3 =2^{-3}, \ c = 2^5, \ d = (\frac{-1}{2})^6=(\frac{1}{2})^6 =2^{-6} \\\\ A. \ ac = 2^7 \cdot 2^5 = 2^{7+5}= 2^{12} \\\\ B. \ bc = 2^{-3} \cdot 2^5 = 2^{-3+5}= 2^2 \\\\ C. \ ab = 2^7 \cdot 2^{-3} = 2^{7+(-3)}=2^4 \\\\ D. \ bd = 2^{-3} \cdot 2^{-6} = 2^{-3 + (-6)} = 2^{-9} \\\\ 2^{-9} < 2^2 < 2^4 < 2^{12} \\\\ bd < bc < ab < ac[/tex]
Z podanych iloczynów najmniejszy jest iloczyn bd.
Odp. D
