[tex]x(x-3) = (2x + 2)^2-x\\\\x^2-3x=4x^2+8x+4-x\\\\ 4x^2+8x+4-x-x^2+3x=0\\\\3x^2+10x+4=0\\\\a=3,\ \ b=10,\ \ c=4\\\\\Delta =b^2-4ac=10^2-4*3*4=100-48=52\\\\\sqrt{\Delta }=\sqrt{52}=\sqrt{4*13}=2\sqrt{13}\\\\x_{1}=\frac{-b-\sqrt{\Delta }}{2a}=\frac{-10-2\sqrt{13}}{2*3}= \frac{2( -5-\sqrt{13})}{2*3}=\frac{-5-\sqrt{13}}{3}[/tex]
[tex]x_{2}=\frac{-b+\sqrt{\Delta }}{2a}=\frac{-10+2\sqrt{13}}{2*3}= \frac{2( -5+\sqrt{13})}{2*3}=\frac{ \sqrt{13}-5}{3}[/tex]
