Odpowiedź :
wzór ogólny alkinów - CnH2n-2
12*n+1*(2n-2)=166
12n+2n-2=166
14n-2=166 / -2
14n=164 / :14
n=12
wzór - C12H22
12*n+1*(2n-2)=166
12n+2n-2=166
14n-2=166 / -2
14n=164 / :14
n=12
wzór - C12H22
Alikn - CxH2x-2
12u*x+1u*(2x-2)=166u
12x+2x-2u=166u
14x-2u=166u / -2u
14x=164 / :14
x=12
C12H12*2-2
C12H22 <-- wzór
12u*x+1u*(2x-2)=166u
12x+2x-2u=166u
14x-2u=166u / -2u
14x=164 / :14
x=12
C12H12*2-2
C12H22 <-- wzór