log₂5+log₂25,6=
log₂144-log₂9=
log₃33-log₃11=


Odpowiedź :

log₂5+log₂25,6=log₂5*25,6==log₂128=log₂2⁷=7
log₂144-log₂9=log₂144:9=log₂16=log₂2⁴=4
log₃33-log₃11=log₃33/11=log₃3=1
log₂5+log₂25,6= log₂(5*25,6) = log₂128 = 7 bo 2⁷ = 128

log₂144-log₂9= log₂ (144:9) = log₂16 = 4 bo 2⁴ = 16

log₃33-log₃11= log₃(33:11) = log₃3 = 1 bo 3¹ = 3