Odpowiedź :
d1 = 6cm
d2 = 8cm
(1/2d1)² + (1/2d2)² = a²
3² + 4² = a²
a² = 9 + 16
a² = 25
a = 5cm -------- bok rombu
P = 1/2 * d1 * d2 = 1/2 * 6 * 8 = 24cm²
Ob = 4 * a = 4 * 5 = 20cm
[tex]d_{1}=6cm\\ d_{2}=8cm\\ \\ P=\frac{d_{1}*d_{2}}{2}\\ P=\frac{6cm*8cm}{2}\\ P=24cm^{2}\\ \\ (\frac{1}{2}*6)^{2}+(\frac{1}{2}*8)^{2}=a^{2}\\ 3^{2}+4^{2}=a^{2}\\ 9+16=a^{2}\\ 25=a^{2}\\ a=\sqrt{25}\\ a=5cm\\ \\ Ob\ rombu=4a\\ Ob\ rombu=4*5cm=20cm [/tex]
Liczę na najlepsze :)