Rozwiązane

(4p-3r)(p+2r)-(3p-r)(p+6r)

4(2a-b)(2a+4B)-(3a-2b)(3b-2a)

Proszę Was ;*

Odpowiedź :

(4p-3r)(p+2r)-(3p-r)(p+6r) = 4p²+8pr-3pr-6r²-(3p²+18pr-pr+6r²) = 4p²+8pr-3pr-6r²-3p²-18pr+pr-6r² = p²-12pr-12r²
Gosia9634viz
(4p-3r)(p+2r)-(3p-r)(p+6r)=(4p*p+4p*2r-3r*p-3r*2r)-(3p*p+3p*6r-r*p-6r*r)=
=4p²+8pr-3pr-6r²-3p²-18pr+pr+6r²=p²-12pr
(4p-3r)(p+2r)-(3p-r)(p+6r) = 4p²+8pr-3pr-6r²-(3p²+18pr-pr+6r²) = 4p²+8pr-3pr-6r²-3p²-18pr+pr-6r² = p²-12pr-12r²
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